Ques 1 Average
The average marks obtained by 40 students of a class is 86. If the 5 highest marks are removed, the average reduces by one mark. The average marks of the top 5 students is.
Ques 2 Average
The average of 25 results is 20. The average of first 12 results is 15 and that of the last 12 results is 18. Then, the 13th result is.
We know that the average of 25 results is 20, so the total sum of all 25 results is.
25×20=500.
We also know that the average of the first 12 results is 15. So, the sum of the first 12 results is .
12×15=180.
Similarly, the average of the last 12 results is 18. So, the sum of the last 12 results is.
12×18=216.
Now, let's express the sum of the 25 results in terms of the sum of the first 12, the 13th result, and the sum of the last 12.
Sum of 25 results=Sum of first 12 results+13th result+Sum of last 12 results.
500=180+x+216.
x=500−180−216.
x=104.
So, the 13th result is 104.
Ques 3 Average
Find the average of 1.11, 0.01, 0.101, 0.001, 0.11 .
Ques 4 Average
The arithmetic mean of the following numbers 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6 and 7, 7, 7, 7, 7, 7, 7 is.
the arithmetic mean of the given numbers, we need to follow the following steps:
1) Sum all the numbers.
2) Count the total number of numbers.
3) Divide the sum by the count.
1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7.
Sum all the numbers:
1+2+2+3+3+3+4+4+4+4+5+5+5+5+5+6+6+6+6+6+6+7+7+7+7+7+7+7.
=1+(2×2)+(3×3)+(4×4)+(5×5)+(6×6)+(7×7).
=1+4+9+16+25+36+49.
=140.
Total number count=28.
arithmetic mean= 140/28=5.
So, the arithmetic mean is 5.
Ques 5 Average
The average of 11 numbers is 63. If the average of first six numbers is 60 and the last six numbers is 65, then the 6th number is.
Ques 6 Average
The average of nine numbers is 50. The average of the first five numbers is 54 and that of the last three numbers is 52. Then the sixth number is.